-3[2y-(y-2)]=2(y+3)

Solution for -3[2y-(y-2)]=2(y+3) equation:

Simplifying
-3[2y + -1(y + -2)] = 2(y + 3)

Reorder the terms:
-3[2y + -1(-2 + y)] = 2(y + 3)
-3[2y + (-2 * -1 + y * -1)] = 2(y + 3)
-3[2y + (2 + -1y)] = 2(y + 3)

Reorder the terms:
-3[2 + 2y + -1y] = 2(y + 3)

Combine like terms: 2y + -1y = 1y
-3[2 + 1y] = 2(y + 3)
[2 * -3 + 1y * -3] = 2(y + 3)
[-6 + -3y] = 2(y + 3)

Reorder the terms:
-6 + -3y = 2(3 + y)
-6 + -3y = (3 * 2 + y * 2)
-6 + -3y = (6 + 2y)

Solving
-6 + -3y = 6 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-6 + -3y + -2y = 6 + 2y + -2y

Combine like terms: -3y + -2y = -5y
-6 + -5y = 6 + 2y + -2y

Combine like terms: 2y + -2y = 0
-6 + -5y = 6 + 0
-6 + -5y = 6

Add '6' to each side of the equation.
-6 + 6 + -5y = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -5y = 6 + 6
-5y = 6 + 6

Combine like terms: 6 + 6 = 12
-5y = 12

Divide each side by '-5'.
y = -2.4

Simplifying
y = -2.4